A box contains 3 blue counters and 8 red counters.
A counter is taken at random and its colour noted.
The counter is put back into the box.
A second counter is then taken at random, and its colour noted.
Work out the probability that
both counters are red,
the two counters are different colours.
This is an "AND" question: 1st counter red AND 2nd counter red.
This is an "AND" and "OR" question: [ 1st red AND 2nd green ] OR [ 1st green AND 2nd red ].
In the second line of working in part (ii) we are multiplying the same two fractions together twice, just 'the other way round'.
It would be possible to write that instead as
That sort of 'shortcut' is often possible in questions like this.
The probability of winning a fairground game is known to be 26%.
If the game is played 4 times find the probability that there is at least one win.
Write down an assumption you have made.
At least one win is the opposite to no losses so use the fact that the sum of all probabilities is 1.
Use the same fact to work out the probability of a loss.
The probability of four losses is an "AND" statement; lose AND lose AND lose AND lose.
Assuming the probability of losing doesn't change, this is
.
P(at least 1 win) = 0.7001 (4 d.p.)
The assumption that we made was that the probability of winning/losing doesn't change between games.
Mathematically this is described as each game being independent.
I.e., the outcome of one game does not affect the outcome of the next (or any other) game.
It has been assumed that the outcome of each game is independent.